=240x-2x^2

Solution for =240x-2x^2 equation:

=240x-2x^2

We move all terms to the left:

-(240x-2x^2)=0

We get rid of parentheses

2x^2-240x=0

a = 2; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·2·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*2}=\frac{480}{4}
=120
$